I have a Windows batch file I\'m creating, but I have to ECHO a large complex string, so I\'m having to put double quotes on either end. The problem is that the quotes are
Using the FOR command to strip the surrounding quotation marks is the most efficient way I've found to do this. In the compact form (Example 2) it's a one-liner.
Example 1: The 5-line (commented) solution.
REM Set your string
SET STR="
Example 2: The 1-liner real-world example.
SET STR="
I find it interesting that the inner echo ignores the redirection characters '<' and '>'.
If you execute ECHO asdfsd>asdfasd you will write file out instead of std out.
Hope this helps :)
Edit:
I thought about it and realized there is an even easier (and less hacky) way of accomplishing the same thing. Use the enhanced variable substitution/expansion (see HELP SET) like this:
SET STR="
That will print all but the first and last characters (your quotation marks). I would recommend using SETLOCAL ENABLEDELAYEDEXPANSION too. If you need to figure out where quotation marks are located in the string you can use FINDSTR to get the character #s.