Primitive cast and assignments in Java

Question

I understand why the following is wrong:

byte a = 3; 
byte b = 8; 
byte c = a + b;  // compile error

It won\'t compile. Expressions alway

Answer 1

It is because 3 and 8 are compile time constants.

Therefore, at the time of compilation happens, compiler can identify that 3 + 8 can fit into a byte variable.

If you make your a and b to final (constant) variable. a + b will become a compile time constant. Therefore, it will compile without any issue.

    final byte a = 3;
    final byte b = 8;
    byte c = a + b;