request.user returns a SimpleLazyObject, how do I “wake” it?

Question

I have the following method:

def _attempt(actor):
    if actor.__class__ != User:
        raise TypeError

Which is called from a view:

Answer 1

For anyone wanting to write a failing "small" unittest for your code, you can generate a wrapped User and stuff it inside a request.

from django.contrib.auth import get_user_model
from django.test import RequestFactory
from django.utils.functional import SimpleLazyObject

user = get_user_model().objects.create_user(
    username='jacob',
    email='jacob@…',
    password='top_secret',
)

factory = RequestFactory()
request = factory.get('/')
request.user = SimpleLazyObject(lambda: user)

See:

• https://github.com/django/django/blob/master/tests/utils_tests/test_lazyobject.py for current tests on the Lazy Objects.

• https://docs.djangoproject.com/en/dev/topics/testing/advanced/#django.test.RequestFactory for latest info on the RequestFactory.