Two different values at the same memory address

Question

Code

#include 
using namespace std;

int main() {
    const int N = 22;
    int * pN = const_cast(&N);
    *pN = 33;
    co         


        

Answer 1

I had the same question (Why am I not able to modify the contents of const int even with const_cast?) . I think answered here wonderfully by everyone. Just adding the assembly output from compiler

This is my original code

const int y = 7;
int* a = new int;
a = const_cast(&y); 
*a = 8;
std::cout << (int)*(&y) << std::endl;

This is the assembly output

std::cout << (int)*(&y) << std::endl;
00381CB6  push        offset std::endl > (03813C5h)  
**00381CBB  push        7**  
00381CBD  mov         ecx,dword ptr [_imp_?cout@std@@3V?$basic_ostream@DU?$char_traits@D@std@@@1@A (03900ACh)]  
00381CC3  call        dword ptr [__imp_std::basic_ostream >::operator<< (03900B8h)]  
00381CC9  mov         ecx,eax  
00381CCB  call        dword ptr [__imp_std::basic_ostream >::operator<< (03900BCh)]  

So the compiler will just replace the const variables with its actual value during compile time.