Two different values at the same memory address

Question

Code

#include 
using namespace std;

int main() {
    const int N = 22;
    int * pN = const_cast(&N);
    *pN = 33;
    co         


        

Answer 1

By stating that N is const, you have promised that you won't modify it. And then you go and modify it. This breaks one of the assumptions the compiler is making, and as a result, the program behaves incorrectly.

This is referred to as "undefined behavior" - after violating an assumption in the language, the behavior of the program is completely undefined. It need not have produced that output - it could've produced 33 for both, or 42, or crashed, or erased your hard drive, or summoned demons through your nasal passages. So, don't modify const values :)