Python create function in a loop capturing the loop variable

Question

What\'s going on here? I\'m trying to create a list of functions:

def f(a,b):
    return a*b

funcs = []

for i in range(0,10):
    funcs.append(lambda x:f(         


        

Answer 1

There's only one i which is bound to each lambda, contrary to what you think. This is a common mistake.

One way to get what you want is:

for i in range(0,10):
    funcs.append(lambda x, i=i: f(i, x))

Now you're creating a default parameter i in each lambda closure and binding to it the current value of the looping variable i.