Array extension to remove object by value

Question

extension Array {
    func removeObject(object: T) {
        var index = find(self, object)
        self.removeAtIndex(index)
    }
}
         


        

Answer 1

After reading all the above, to my mind the best answer is:

func arrayRemovingObject(object: U, # fromArray:[U]) -> [U] {
  return fromArray.filter { return $0 != object }
}

Sample:

var myArray = ["Dog", "Cat", "Ant", "Fish", "Cat"]
myArray = arrayRemovingObject("Cat", fromArray:myArray )

Swift 2 (xcode 7b4) array extension:

extension Array where Element: Equatable {  
  func arrayRemovingObject(object: Element) -> [Element] {  
    return filter { $0 != object }  
  }  
}  

Sample:

var myArray = ["Dog", "Cat", "Ant", "Fish", "Cat"]
myArray = myArray.arrayRemovingObject("Cat" )

Swift 3.1 update

Came back to this now that Swift 3.1 is out. Below is an extension which provides exhaustive, fast, mutating and creating variants.

extension Array where Element:Equatable {
    public mutating func remove(_ item:Element ) {
        var index = 0
        while index < self.count {
            if self[index] == item {
                self.remove(at: index)
            } else {
                index += 1
            }
        }
    }

    public func array( removing item:Element ) -> [Element] {
        var result = self
        result.remove( item )
        return result
    }
}

Samples:

// Mutation...
      var array1 = ["Cat", "Dog", "Turtle", "Cat", "Fish", "Cat"]
      array1.remove("Cat")
      print(array1) //  ["Dog", "Turtle", "Socks"]

// Creation...
      let array2 = ["Cat", "Dog", "Turtle", "Cat", "Fish", "Cat"]
      let array3 = array2.array(removing:"Cat")
      print(array3) // ["Dog", "Turtle", "Fish"]