How to loop all files in sorted order in Bash?

Question

I am looping all files in directory with following command:

for i in *.fas; do some_code; done;

However, I get order like this:

<         


        

Answer 1

Like @Kusalananda's solution (perhaps easier to remember?) but catering for all files(?):

array=("$(ls |sed 's/[^0-9]*\([0-9]*\)\..*/\1 &/'| sort -n | sed 's/^[^ ]* //')")
for x in "${array[@]}";do echo "$x";done

In essence add a sort key, sort, remove sort key.

EDIT: moved comment to appropriate solution