C++11 variable number of arguments, same specific type

Question

Question is simple, how would I implement a function taking a variable number of arguments (alike the variadic template), however where all arguments have the same type, say

Answer 1

Because I don't think I saw this solution, you could write a specific function for every type (in your case, just int) then a forwarding function taking variadic argument types.

Write each specific case:

then for each specific case:

// only int in your case
void func(int i){
    std::cout << "int i = " << i << std::endl;
}

Then your forwarding function like this:

template
void func(Arg0 &&arg0, Arg1 &&arg1, Args &&... args){
    func(std::forward(arg0));
    func(std::forward(arg1), std::forward(args)...);
}

This is good because it is expandable for when you want to accept maybe another type too.

Used like this:

int main(){
    func(1, 2, 3, 4); // works fine
    func(1.0f, 2.0f, 3.0f, 4.0f); // compile error, no func(float)
}