One-liner to check whether an iterator yields at least one element?

Question

Currently I\'m doing this:

try:
    something = iterator.next()
    # ...
except StopIteration:
    # ...

But I would like an expression th

Answer 1

A little late, but... You could turn the iterator into a list and then work with that list:

# Create a list of objects but runs out the iterator.
l = [_ for _ in iterator]

# If the list is not empty then the iterator had elements; else it was empty.
if l :
    pass # Use the elements of the list (i.e. from the iterator)
else :
    pass # Iterator was empty, thus list is empty.