One-liner to check whether an iterator yields at least one element?

Question

Currently I\'m doing this:

try:
    something = iterator.next()
    # ...
except StopIteration:
    # ...

But I would like an expression th

Answer 1

What about:

In [1]: i=iter([])

In [2]: bool(next(i,False))
Out[2]: False

In [3]: i=iter([1])

In [4]: bool(next(i,False))
Out[4]: True