How to incrementally sample without replacement?

Question

Python has my_sample = random.sample(range(100), 10) to randomly sample without replacement from [0, 100).

Suppose I have sampled n

Answer 1

It's surprising this is not already implemented in one of the core functions, but here is the clean version, that returns the sampled values and the list without replacement:

def sample_n_points_without_replacement(n, set_of_points):
    sampled_point_indices = random.sample(range(len(set_of_points)), n)
    sampled_point_indices.sort(reverse=True)
    sampled_points = [set_of_points[sampled_point_index] for sampled_point_index in sampled_point_indices]
    for sampled_point_index in sampled_point_indices:
        del(set_of_points[sampled_point_index])
    return sampled_points, set_of_points