Why doesn't Java offer operator overloading?

Question

Coming from C++ to Java, the obvious unanswered question is why didn\'t Java include operator overloading?

Isn\'t Complex a, b, c; a = b + c; much simpl

Answer 1

I think this may have been a conscious design choice to force developers to create functions whose names clearly communicate their intentions. In C++ developers would overload operators with functionality that would often have no relation to the commonly accepted nature of the given operator, making it nearly impossible to determine what a piece of code does without looking at the definition of the operator.