Why doesn't Java offer operator overloading?

Question

Coming from C++ to Java, the obvious unanswered question is why didn\'t Java include operator overloading?

Isn\'t Complex a, b, c; a = b + c; much simpl

Answer 1

Check out Boost.Units: link text

It provides zero-overhead Dimensional analysis through operator overloading. How much clearer can this get?

quantity     F = 2.0*newton;
quantity    dx = 2.0*meter;
quantity    E = F * dx;
std::cout << "Energy = " << E << endl;

would actually output "Energy = 4 J" which is correct.