How to get every Nth element of an infinite list in Haskell?

Question

More specifically, how do I generate a new list of every Nth element from an existing infinite list?

E.g. if the list is [5, 3, 0, 1, 8, 0, 3, 4, 0, 93, 211, 0

Answer 1

An uglier, and more limited version of the accepted answer

every :: Eq a => Int -> [a] -> [a]
every n xs = if rest == [] 
                then [] 
                else head rest : every n (tail rest)
    where rest = drop (n-1) xs

For "line golfing" it can be written like this:

every n xs = if rest == [] then [] else head rest : every n (tail rest) 
    where rest = drop (n-1) xs

(It's more limited because it has an unnecessary Eq a constraint.)