How to get every Nth element of an infinite list in Haskell?

Question

More specifically, how do I generate a new list of every Nth element from an existing infinite list?

E.g. if the list is [5, 3, 0, 1, 8, 0, 3, 4, 0, 93, 211, 0

Answer 1

MHarris's answer is great. But I like to avoid using \, so here's my golf:

extractEvery n
  = map snd . filter fst
  . zip (cycle (replicate (n-1) False ++ [True]))