How to get every Nth element of an infinite list in Haskell?

Question

More specifically, how do I generate a new list of every Nth element from an existing infinite list?

E.g. if the list is [5, 3, 0, 1, 8, 0, 3, 4, 0, 93, 211, 0

Answer 1

Starting at the first element:

everyf n [] = []
everyf n as  = head as : everyf n (drop n as)

Starting at the nth element:

every n = everyf n . drop (n-1)