How to get every Nth element of an infinite list in Haskell?

Question

More specifically, how do I generate a new list of every Nth element from an existing infinite list?

E.g. if the list is [5, 3, 0, 1, 8, 0, 3, 4, 0, 93, 211, 0

Answer 1

My version using drop:

every n xs = case drop (n-1) xs of
              (y:ys) -> y : every n ys
              [] -> []

Edit: this also works for finite lists. For infinite lists only, Charles Stewart's solution is slightly shorter.