create file of particular size in python

Question

I want to create a file of particular size (say, 1GiB). The content is not important since I will fill stuff into it.

What I am doing is:

f = open(\"         


        

Answer 1

The question has been answered before. Not sure whether the solution is cross platform, but it works in Windows (NTFS file system) flawlessly.

with open("file.to.create", "wb") as out:
    out.truncate(1024 * 1024 * 1024)

This answer uses seek and write:

with open("file.to.create", "wb") as out:
    out.seek((1024 * 1024 * 1024) - 1)
    out.write('\0')