Get the name of the caller script in bash script

Question

Let\'s assume I have 3 shell scripts:

script_1.sh

#!/bin/bash
./script_3.sh

script_2.sh

Answer 1

Declare this:

PARENT_NAME=`ps -ocomm --no-header $PPID`

Thus you'll get a nice variable $PARENT_NAME that holds the parent's name.