Get the name of the caller script in bash script

Question

Let\'s assume I have 3 shell scripts:

script_1.sh

#!/bin/bash
./script_3.sh

script_2.sh

Answer 1

Couple of useful files things kept in /proc/$PPID here

• /proc/*some_process_id*/exe A symlink to the last executed command under *some_process_id*
• /proc/*some_process_id*/cmdline A file containing the last executed command under *some_process_id* and null-byte separated arguments

So a slight simplification.

sed 's/\x0/ /g' "/proc/$PPID/cmdline"