Get the name of the caller script in bash script

Question

Let\'s assume I have 3 shell scripts:

script_1.sh

#!/bin/bash
./script_3.sh

script_2.sh

Answer 1

In case you are sourceing instead of calling/executing the script there is no new process forked and thus the solutions with ps won't work reliably.

Use bash built-in caller in that case.

$ cat h.sh 
#! /bin/bash 
function warn_me() { 
    echo "$@" 
    caller 
} 
$ cat g.sh 
#!/bin/bash 
source h.sh 
warn_me "Error: You didn't do something" 
$ . g.sh 
Error: You didn't do something 3 
g.sh
$

Source