How do I reliably split a string in Python, when it may not contain the pattern, or all n elements?

Question

In Perl I can do:

my ($x, $y) = split /:/, $str;

And it will work whether or not the string contains the pattern.

In Python, howeve

Answer 1

If you're splitting into just two parts (like in your example) you can use str.partition() to get a guaranteed argument unpacking size of 3:

>>> a, sep, b = 'foo'.partition(':')
>>> a, sep, b
('foo', '', '')

str.partition() always returns a 3-tuple, whether the separator is found or not.

Another alternative for Python 3.x is to use extended iterable unpacking:

>>> a, *b = 'foo'.split(':')
>>> a, b
('foo', [])

This assigns the first split item to a and the list of remaining items (if any) to b.