Slicing a list into a list of sub-lists [duplicate]

Answer 1

I like SilentGhost's solution.

My solution uses functional programming in python:

group = lambda t, n: zip(*[t[i::n] for i in range(n)])
group([1, 2, 3, 4], 2)

gives:

[(1, 2), (3, 4)]

This assumes that the input list size is divisible by the group size. If not, unpaired elements will not be included.