'init(start:end:)' is deprecated: it will be removed in Swift 3. Use the '..<' operator

Question

I\'m using the following code:

var continousDigitsRange:Range = Range(start: 0, end: 0)

Since update to Xcode 7.3 (Sw

Answer 1

I have always had a function to get the substring range of a string. Here is my updated function for Swift 3:

func getSubStringRange(fullString: String, fromIndex: Int, subStringSize: Int) -> Range {
    let startIndex = fullString.characters.index(fullString.startIndex, offsetBy: fromIndex)
    let endIndex = fullString.characters.index(startIndex, offsetBy: subStringSize)

    let subStringRange = startIndex..

The function is pretty self explanatory - You pass in a string(fullString), the index of that string where the substring starts(fromIndex) and how big the subString is(subStringSize).

Example:

let greeting = "Hi, my name is Nathaniel"
let getName = greeting[getSubStringRange(fullString: greeting, fromIndex: 15, subStringSize: 9)]

print("Name: \(getName)")

-> Prints: "Name: Nathaniel"