Are default enum values in C the same for all compilers?

Question

When declaring an enum as shown below, do all C compilers set the default values as x=0, y=1, and z=2 on both Linux and Windows system

Answer 1

C99 Standard

The N1265 C99 draft says at 6.7.2.2/3 "Enumeration specifiers"

An enumerator with = defines its enumeration constant as the value of the constant expression. If the first enumerator has no =, the value of its enumeration constant is 0. Each subsequent enumerator with no = defines its enumeration constant as the value of the constant expression obtained by adding 1 to the value of the previous enumeration constant. (The use of enumerators with = may produce enumeration constants with values that duplicate other values in the same enumeration.)

So the following always holds on conforming implementations:

main.c

#include 
#include 

enum E {
    E0,
    E1,
    E2 = 3,
    E3 = 3,
    E4,
    E5 = INT_MAX,
#if 0
    /* error: overflow in enumeration values */
    E6,
#endif
};

int main(void) {
    /* If unspecified, the first is 0. */
    assert(E0 == 0);
    assert(E1 == 1);
    /* Repeated number, no problem. */
    assert(E2 == 3);
    assert(E3 == 3);
    /* Continue from the last one. */
    assert(E4 == 4);
    assert(E5 == INT_MAX);
    return 0;
}

Compile and run:

gcc -std=c99 -Wall -Wextra -pedantic -o main.out main.c
./main.out

Tested in Ubuntu 16.04, GCC 6.4.0.