std::copy to std::cout for std::pair

Question

I have next code:

#include 
#include 
#include 

Answer 1

I've founded one new elegant way to solve this problem.
I've got many interest ideas when read answers:

• wrap iterator, for transform std::pair to std::string;
  
• wrap std::pair, for have a chance to overload operator<<(...);
  
• use usual std::for_each with printing functor;
  
• use std::for_each with boost::labda - looks nice, except accessing to std::pair< >::first and std::pair< >::second members;
  

I think I will use all of this ideas in future for solve different other problems.
But for this case I've understaded that I can formulate my bproblem as "transform map's data to strings and write them to output stream" instead "copy map's data to ouput stream". My solution looks like:

namespace
{
std::string toString( const std::pair< size_t, size_t >& data)
{
    std::ostringstream str;
    str << data.first << ", " << data.second;
    return str.str();
}
} // namespace anonymous

std::transform( 
    some_map.begin(), 
    some_map.end(), 
    std::ostream_iterator< std::string >( std::cout, "\n" ),
    toString );

I think this method is most short and expressive than others.