Check if a Bash array contains a value

Question

In Bash, what is the simplest way to test if an array contains a certain value?

Answer 1

Combining a few of the ideas presented here you can make an elegant if statment without loops that does exact word matches.

find="myword"
array=(value1 value2 myword)
if [[ ! -z $(printf '%s\n' "${array[@]}" | grep -w $find) ]]; then
  echo "Array contains myword";
fi

This will not trigger on word or val, only whole word matches. It will break if each array value contains multiple words.