What is the shortest way to initialize List of strings in java?

Question

I am searching for the shortest way (in code) to initialize list of strings and array of strings, i.e. list/array containing \"s1\", \"s2\", \"s3\" string elements.

Answer 1

With Eclipse Collections, you can write the following:

List list = Lists.mutable.with("s1", "s2", "s3");

You can also be more specific about the types and whether they are Mutable or Immutable.

MutableList mList = Lists.mutable.with("s1", "s2", "s3");
ImmutableList iList = Lists.immutable.with("s1", "s2", "s3");

You can also do the same with Sets, Bags and Maps:

Set set = Sets.mutable.with("s1", "s2", "s3");
MutableSet mSet = Sets.mutable.with("s1", "s2", "s3");
ImmutableSet iSet = Sets.immutable.with("s1", "s2", "s3");

Bag bag = Bags.mutable.with("s1", "s2", "s3");
MutableBag mBag = Bags.mutable.with("s1", "s2", "s3");
ImmutableBag iBag = Bags.immutable.with("s1", "s2", "s3");

Map map = 
    Maps.mutable.with("s1", "s1", "s2", "s2", "s3", "s3");
MutableMap mMap = 
    Maps.mutable.with("s1", "s1", "s2", "s2", "s3", "s3");
ImmutableMap iMap = 
    Maps.immutable.with("s1", "s1", "s2", "s2", "s3", "s3");

There are factories for SortedSets, SortedBags and SortedMaps as well.

SortedSet sortedSet = SortedSets.mutable.with("s1", "s2", "s3");
MutableSortedSet mSortedSet = SortedSets.mutable.with("s1", "s2", "s3");
ImmutableSortedSet iSortedSet = SortedSets.immutable.with("s1", "s2", "s3");

SortedBag sortedBag = SortedBags.mutable.with("s1", "s2", "s3");
MutableSortedBag mSortedBag = SortedBags.mutable.with("s1", "s2", "s3");
ImmutableSortedBag iSortedBag = SortedBags.immutable.with("s1", "s2", "s3");

SortedMap sortedMap =
        SortedMaps.mutable.with("s1", "s1", "s2", "s2", "s3","s3");
MutableSortedMap mSortedMap =
        SortedMaps.mutable.with("s1", "s1", "s2", "s2", "s3","s3");
ImmutableSortedMap iSortedMap =
        SortedMaps.immutable.with("s1", "s1", "s2", "s2", "s3","s3");

Note: I am a committer for Eclipse Collections.