Difference between *ptr[10] and (*ptr)[10]

Question

For the following code:

    int (*ptr)[10];
    int a[10]={99,1,2,3,4,5,6,7,8,9};
    ptr=&a;
    printf(\"%d\",(*ptr)[1]);

What should

Answer 1

int(*)[10] is a pointer to an int array with 10 members. i.e it points to int a[10].

where as int *[10] is array of integer pointers

#include 
int main()
{

int *ptr[10];
int a[10]={0,1,2,3,4,5,6,7,8,9};

printf("\n%p  %p", ptr[0], a);

*ptr=a; //ptr[0] is assigned with address of array a.

printf("\n%p  %p", ptr[0], a); //gives you same address

printf("\n%d",*ptr[0]); //Prints zero. If *ptr[1] is given then *(ptr + 1) i.e ptr[1] is considered which is uninitialized one.

return 0;
}