Difference between *ptr[10] and (*ptr)[10]

Question

For the following code:

    int (*ptr)[10];
    int a[10]={99,1,2,3,4,5,6,7,8,9};
    ptr=&a;
    printf(\"%d\",(*ptr)[1]);

What should

Answer 1

int (*ptr)[10];

is a pointer to an array of 10 ints.

int *ptr[10];

is an array of 10 pointers.

Reason for segfault:

*ptr=a; printf("%d",*ptr[1]);

Here you are assigning the address of array a to ptr which would point to the element a[0]. This is equivalent to: *ptr=&a[0];

However, when you print, you access ptr[1] which is an uninitialized pointer which is undefined behaviour and thus giving segfault.