Correct way to inherit from std::exception

Question

I\'ve just created exception hierarchy and wanted to pass char* to constructor of one of my derived classes with a message telling what\'s wrong, but apparently

Answer 1

If your goal is to create an exception so that you do not throw a generic exception (cpp:S112) you may just want to expose the exception you inherit from (C++11) with a using declaration.

Here is a minimal example for that:

#include 
#include 

struct myException : std::exception
{
    using std::exception::exception;
};

int main(int, char*[])
{
    try
    {
        throw myException{ "Something Happened" };
    }
    catch (myException &e)
    {
        std::cout << e.what() << std::endl;
    }
    return{ 0 };
}

As Kilian points out in the comment section the example depends on a specific implementation of std::exception that offers more constructors than are mentioned here.

In order to avoid that you can use any of the convenience classes predefined in the header . See these "Exception categories" for inspiration.