Why doesn't this reinterpret_cast compile?

Question

I understand that reinterpret_cast is dangerous, I\'m just doing this to test it. I have the following code:

int x = 0;
double y = reinterpret_c         


        

Answer 1

Casting an int to a double doesn't require a cast. The compiler will perform the assignment implicitly.

The reinterpret_cast is used with pointers and references, e.g., casting an int * to a double *.