Why doesn't this reinterpret_cast compile?

Question

I understand that reinterpret_cast is dangerous, I\'m just doing this to test it. I have the following code:

int x = 0;
double y = reinterpret_c         


        

Answer 1

If you are trying to convert the bits of your int to a the representation of a double, you need to cast the address not the value. You must also make sure the sizes match:

uint64_t x = 0x4045000000000000;
double y = *reinterpret_cast(&x);