How is the getBBox() SVGRect calculated?

Question

I have a g element that contains one or more path elements. As I mentioned in another question, I scale and translate the g element by

Answer 1

there are at least 2 easy but somewhat hacky ways to do what you ask... if there are nicer (less hacky) ways, i haven't found them yet

EASY HACKy #1:
a) set up a rect that matches the "untransformed" bbox that group.getBBox() is returning
b) apply the group's "unapplied transform" to that rect
c) rect.getBBox() should now return the bbox you're looking for

EASY HACKY #2: (only tested in chrome)
a) use element.getBoundingClientRect(), which returns enough info for you to construct the bbox you're looking for