Open Facebook page from Android app?

Question

from my Android app, I would like to open a link to a Facebook profile in the official Facebook app (if the app is installed, of course). For iPhone, there exists the

Answer 1

I have created a method to open facebook page into facebook app, if app is not existing then opening in chrome

    String socailLink="https://www.facebook.com/kfc";
    Intent intent = new Intent(Intent.ACTION_VIEW);
    String facebookUrl = Utils.getFacebookUrl(getActivity(), socailLink);
    if (facebookUrl == null || facebookUrl.length() == 0) {
        Log.d("facebook Url", " is coming as " + facebookUrl);
        return;
    }
    intent.setData(Uri.parse(facebookUrl));
    startActivity(intent);

Utils.class add these method

public static String getFacebookUrl(FragmentActivity activity, String facebook_url) {
    if (activity == null || activity.isFinishing()) return null;

    PackageManager packageManager = activity.getPackageManager();
    try {
        int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
        if (versionCode >= 3002850) { //newer versions of fb app
            Log.d("facebook api", "new");
            return "fb://facewebmodal/f?href=" + facebook_url;
        } else { //older versions of fb app
            Log.d("facebook api", "old");
            return "fb://page/" + splitUrl(activity, facebook_url);
        }
    } catch (PackageManager.NameNotFoundException e) {
        Log.d("facebook api", "exception");
        return facebook_url; //normal web url
    }
}

and this

 /***
 * this method used to get the facebook profile name only , this method split domain into two part index 0 contains https://www.facebook.com and index 1 contains after / part
 * @param context contain context
 * @param url contains facebook url like https://www.facebook.com/kfc
 * @return if it successfully split then return "kfc"
 *
 * if exception in splitting then return "https://www.facebook.com/kfc"
 *
 */
 public static String splitUrl(Context context, String url) {
    if (context == null) return null;
    Log.d("Split string: ", url + " ");
    try {
        String splittedUrl[] = url.split(".com/");
        Log.d("Split string: ", splittedUrl[1] + " ");
        return splittedUrl.length == 2 ? splittedUrl[1] : url;
    } catch (Exception ex) {
        return url;
    }
}