I have a data frame similar to the one below:
Name Volume Value May21 23 21321 James 12 12311 Adi22 11 4435 Hello 34 32454 Gi
You can do it like so:
df.Name = df.Name.str.replace('\d+', '')
To play and explore, check the online Regular expression demo here: https://regex101.com/r/Y6gJny/2
Whatever is matched by the pattern \d+ i.e 1 or more digits, will be replaced by empty string.
\d+