Linux bash script to extract IP address

Question

I want to make big script on my Debian 7.3 ( something like translated and much more new user friendly enviroment ). I have a problem. I want to use only some of the informa

Answer 1

In my opinion the simplest and most elegant way to achieve what you need is this:

ip route get 8.8.8.8 | tr -s ' ' | cut -d' ' -f7

---

ip route get [host] - gives you the gateway used to reach a remote host e.g.:

8.8.8.8 via 192.168.0.1 dev enp0s3  src 192.168.0.109

---

tr -s ' ' - removes any extra spaces, now you have uniformity e.g.:

8.8.8.8 via 192.168.0.1 dev enp0s3 src 192.168.0.109

---

cut -d' ' -f7 - truncates the string into ' 'space separated fields, then selects the field #7 from it e.g.:

192.168.0.109