How do I test (in one line) if command output contains a certain string?

Question

In one line of bash, how do I return an exit status of 0 when the output of /usr/local/bin/monit --version doesn\'t contain exactly 5.5 and an exit

Answer 1

Test the return value of grep:

sudo service xyz status | grep 'not' &> /dev/null
if [ $? == 0 ]; then
   echo "whateveryouwant"
fi

I would recommend cron, it works fine with SALT stack