How do I test (in one line) if command output contains a certain string?

Question

In one line of bash, how do I return an exit status of 0 when the output of /usr/local/bin/monit --version doesn\'t contain exactly 5.5 and an exit

Answer 1

[ $(/usr/local/bin/monit --version) == "5.5" ] 

eg-1: check for success

[ $(/usr/local/bin/monit --version) == "5.5" ] && echo "OK"

eg-2: check for failure

    [ $(/usr/local/bin/monit --version) == "5.5" ] || echo "NOT OK"

or, to just check if the output contains 5.5:

[[ $(/usr/local/bin/monit --version) =~ "5.5" ]] || echo "NOT OK"