Python Method overriding, does signature matter?

Question

Lets say I have

class Super():
  def method1():
    pass

class Sub(Super):
  def method1(param1, param2, param3):
      stuff

Is this corr

Answer 1

You could do something like this if it's ok to use default arguments:

>>> class Super():
...   def method1(self):
...     print("Super")
...
>>> class Sub(Super):
...   def method1(self, param1="X"):
...     super(Sub, self).method1()
...     print("Sub" + param1)
...
>>> sup = Super()
>>> sub = Sub()
>>> sup.method1()
Super
>>> sub.method1()
Super
SubX