Python Method overriding, does signature matter?

Question

Lets say I have

class Super():
  def method1():
    pass

class Sub(Super):
  def method1(param1, param2, param3):
      stuff

Is this corr

Answer 1

In python, all class methods are "virtual" (in terms of C++). So, in the case of your code, if you'd like to call method1() in super class, it has to be:

class Super():
    def method1(self):
        pass

class Sub(Super):
    def method1(self, param1, param2, param3):
       super(Sub, self).method1() # a proxy object, see http://docs.python.org/library/functions.html#super
       pass

And the method signature does matter. You can't call a method like this:

sub = Sub()
sub.method1()