How to get current time and date in C++?

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刺人心
刺人心 2020-11-22 06:55

Is there a cross-platform way to get the current date and time in C++?

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  •  挽巷
    挽巷 (楼主)
    2020-11-22 07:19

    This works with G++ I'm not sure if this helps you. Program output:

    The current time is 11:43:41 am
    The current date is 6-18-2015 June Wednesday 
    Day of month is 17 and the Month of year is 6,
    also the day of year is 167 & our Weekday is 3.
    The current year is 2015.
    

    Code :

    #include 
    #include 
    #include 
    #include 
    #include 
    
    using namespace std;
    
    const std::string currentTime() {
    time_t now = time(0);
    struct tm tstruct;
    char buf[80];
    tstruct = *localtime(&now);
    strftime(buf, sizeof(buf), "%H:%M:%S %P", &tstruct);
    return buf;
    }
    
    const std::string currentDate() {
    time_t now = time(0);
    struct tm tstruct;
    char buf[80];
    tstruct = *localtime(&now);
    strftime(buf, sizeof(buf), "%B %A ", &tstruct);
    return buf;
    }
    
    int main() {
        cout << "\033[2J\033[1;1H"; 
    std:cout << "The current time is " << currentTime() << std::endl;
        time_t t = time(0);   // get time now
        struct tm * now = localtime( & t );
        cout << "The current date is " << now->tm_mon + 1 << '-' 
             << (now->tm_mday  + 1) << '-'
             <<  (now->tm_year + 1900) 
             << " " << currentDate() << endl; 
    
     cout << "Day of month is " << (now->tm_mday) 
          << " and the Month of year is " << (now->tm_mon)+1 << "," << endl;
        cout << "also the day of year is " << (now->tm_yday) 
             << " & our Weekday is " << (now->tm_wday) << "." << endl;
        cout << "The current year is " << (now->tm_year)+1900 << "." 
             << endl;
     return 0;  
    }
    

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