Elegantly determine if more than one boolean is “true”

Question

I have a set of five boolean values. If more than one of these are true I want to excecute a particular function. What is the most elegant way you can think of that would al

Answer 1

If your flags are packed into one word then Michael Burr's solution will work. However, the loop is not necessary:

int moreThanOneBitSet( unsigned int v)
{
    return (v & (v - 1)) != 0;
}

example

 v (binary) | v - 1 | v&(v-1) | result
------------+-------+---------+--------
       0000 |  1111 |    0000 |  false
       0001 |  0000 |    0000 |  false
       0010 |  0001 |    0000 |  false
       0011 |  0010 |    0010 |   true
       .... |  .... |    .... |   ....
       1000 |  0111 |    0000 |  false
       1001 |  1000 |    1000 |   true
       1010 |  1001 |    1000 |   true
       1011 |  1010 |    1010 |   true
       1100 |  1011 |    1000 |   true
       1101 |  1100 |    1100 |   true
       1110 |  1101 |    1100 |   true
       1111 |  1110 |    1110 |   true