Arrange 0's & 1's in a array

Question

This is one of an interview question which I had recently. I would like to know others perception of approach for this problem.

Question:

Yo

Answer 1

Here's my (complete) stab at it in C#. It generates the list and sticks random employees in, so make numberOfEmployees whatever you like. I realize there is probably a simpler way of doing this, because the original poster specified that there are an equal amount of 0-dept employees as 1-dept employees, but I couldn't help myself.

struct Employee
{
    public Employee(string name, int dept)
    {
        this.name = name;
        this.dept = dept;
    }

    public string name;
    public int dept;
}

class Program
{
    static void Main(string[] args)
    {
        int numberOfEmployees = 100;
        Random r = new Random();

        Employee[] emps = new Employee[numberOfEmployees];
        var empBuf = new Employee[numberOfEmployees];
        int nextAvail = 0;

        // Initialize array of employees with random data
        for (int i = 0; i < numberOfEmployees; i++)
        {
            emps[i] = new Employee("x" + i.ToString(), r.Next(0, 2));
        }

        Console.WriteLine("Old list:");
        foreach (var e in emps)
        {
            Console.WriteLine("Name: {0}, Dept: {1}", e.name, e.dept);
        }

        // throw employees with dept == 1 in first
        for (int i = 0; i < numberOfEmployees; i++)
        {
            if (emps[i].dept == 1)
            {
                empBuf[nextAvail] = emps[i];
                nextAvail++;
            }
        }

        // stick the employees with dept == 0 in last
        for (int i = 0; i < numberOfEmployees; i++)
        {
            if (emps[i].dept == 0)
            {
                empBuf[nextAvail] = emps[i];
                nextAvail++;
            }
        }


        Console.WriteLine("New list:");
        foreach (Employee e in empBuf)
        {
            Console.WriteLine("Name: {0}, Dept: {1}", e.name, e.dept);
        }

    }
}