Does Java support default parameter values?

Question

I came across some Java code that had the following structure:

public MyParameterizedFunction(String param1, int param2)
{
    this(param1, param2, false);
}         


        

Answer 1

No, but you can very easily emulate them. What in C++ was:

public: void myFunction(int a, int b=5, string c="test") { ... }

In Java, it will be an overloaded function:

public void myFunction(int a, int b, string c) { ... }

public void myFunction(int a, int b) {
    myFunction(a, b, "test");
}

public void myFunction(int a) {
    myFunction(a, 5);
}

Earlier was mentioned, that default parameters caused ambiguous cases in function overloading. That is simply not true, we can see in the case of the C++: yes, maybe it can create ambiguous cases, but these problem can be easily handled. It simply wasn't developed in Java, probably because the creators wanted a much simpler language as C++ was - if they had right, is another question. But most of us don't think he uses Java because of its simplicity.