Python: How to run unittest.main() for all source files in a subdirectory?

Question

I am developing a Python module with several source files, each with its own test class derived from unittest right in the source. Consider the directory structure:

Answer 1

In case it happens to help anyone, here is the approach I arrived at for solving this problem. I had the use case where I have the following directory structure:

mypackage/
    tests/
        test_category_1/
            tests_1a.py
            tests_1b.py
            ...
        test_category_2/
            tests_2a.py
            tests_2b.py
            ...
        ...

and I want all of the following to work in the obvious way and to be able to be supplied the same commandline arguments as are accepted by unittest:

python -m mypackage.tests
python -m mypackage.tests.test_category_1
python -m mypackage.tests.test_category_1.tests_1a

The solution was to set up mypackage/tests/__init__.py like this:

import unittest

def prepare_load_tests_function (the__path__):
    test_suite = unittest.TestLoader().discover(the__path__[0])
    def load_tests (_a, _b, _c):
        return test_suite
    return load_tests

and to set up mypackage/tests/__main__.py like this:

import unittest
from . import prepare_load_tests_function, __path__

load_tests = prepare_load_tests_function(__path__)
unittest.main()

and to copy and paste an empty __init__.py and the following __main__.py in each mypackage/tests/test_category_n/:

import unittest
from .. import prepare_load_tests_function
from . import __path__

load_tests = prepare_load_tests_function(__path__)
unittest.main()

and also to add the standard if __name__ == '__main__': unittest.main() in each actual tests file.

(Works for me on Python 3.3 on Windows, ymmv.)