How do you translate this regular-expression idiom from Perl into Python?

Question

I switched from Perl to Python about a year ago and haven\'t looked back. There is only one idiom that I\'ve ever found I can do more easily in Perl than in Python:<

Answer 1

import re

s = '1.23 Million equals to 1230000'

s = re.sub("([\d.]+)(\s*)Million", lambda m: str(round(float(m.groups()[0]) * 1000_000))+m.groups()[1], s)

print(s)

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1230000 equals to 1230000