How to generate a GUID in Oracle?

Question

Is it possible to auto-generate a GUID into an Insert statement?

Also, what type of field should I use to store this GUID?

Answer 1

sys_guid() is a poor option, as other answers have mentioned. One way to generate UUIDs and avoid sequential values is to generate random hex strings yourself:

select regexp_replace(
    to_char(
        DBMS_RANDOM.value(0, power(2, 128)-1),
        'FM0xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'),
    '([a-f0-9]{8})([a-f0-9]{4})([a-f0-9]{4})([a-f0-9]{4})([a-f0-9]{12})',
    '\1-\2-\3-\4-\5') from DUAL;