Writing FizzBuzz

Question

Reading the coding horror, I just came across the FizzBuzz another time.

The original post is here: Coding Horror: Why Can\'t Programmers.. Program?

For thos

Answer 1

Ok, what the heck, here's the solution I've come to like :)

public void DoFizzBuzz()
{
    for (int i = 1; i <= 100; ++i)
    {
        bool isDivisibleByThree = i % 3 == 0;
        bool isDivisibleByFive = i % 5 == 0;

        if (isDivisibleByThree || isDivisibleByFive)
        {
            if (isDivisibleByThree)
                cout << "Fizz";

            if (isDivisibleByFive)
                cout << "Buzz";
        }
        else
        {
            cout << i;
        }
        cout << endl;
    }
}

Obviously, this is not the fastest solution, but I like it because it emphasizes readability and makes the "FizzBuzz" case no longer a special case, but something that will happen naturally through the code path.

In the end, what I love most about this question whenever it comes up is that we get to see just how many different solutions ppl can come up with.